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Probability

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Question : 39 of 127

Marks: +1, -0

If an unbiased die is rolled once, the odds in favour of getting a point which is a multiple of 3 is

$1: 2$
$2:1$
$1: 3$
$3: 1$

Solution:

Concept:

Odds in favour = number of favourable outcomes : number of unfavourable outcomes.

Explanation:

An unbiased die has outcomes

\{1,2,3,4,5,6\}

.

Multiples of

3

are

3

and

6

, so favourable outcomes =

2

.

Unfavourable outcomes =

6 - 2 = 4

.

Odds in favour =

2 : 4 = 1 : 2

.

Answer:

Option A:

1 : 2

.

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