Probability

Concept:The events "Ram stands first" and "Rahim stands first" are mutually exclusive because only one student can stand first.Explanation:The probability that Ram stands first is $\frac{1}{3}$ and the probability that Rahim stands first is $\frac{1}{5}$.Since both events cannot occur together, the probability that either of them stands first is the sum of their individual probabilities.So, required probability = $\frac{1}{3} + \frac{1}{5} = \frac{5}{15} + \frac{3}{15} = \frac{8}{15}$.Answer:$\frac{8}{15}$