Concept:Differentiate the given integral equation to obtain a simple differential equation.Explanation:Given ∫xf(x)dx=2f(x).Differentiate both sides with respect to x:dxd[∫xf(x)dx]=dxd[2f(x)].Left side becomes xf(x) (by Fundamental Theorem of Calculus).Right side becomes 2f′(x).Hence xf(x)=2f′(x) which gives f′(x)=2xf(x).Solve: dxdf=2xf⇒fdf=2xdx.Integrate: ln∣f∣=x2+C⇒f(x)=kex2.Now check the original equation: ∫x⋅kex2dx=2kex2=2f(x) holds for any constant k.Among the options, option D is 2ex2 which matches k=21.Answer:2ex2