If x/b+c = y/c+a = z/a+b, then

Correct Answer is : x−yb−a=y−zc−b=z−xa−cx-y/b-a = y-z/c-b = z-x/a-cb−ax−y=c−by−z=a−cz−x

Correct Answer is : x−yb−a=y−zc−b=z−xa−cx-y/b-a = y-z/c-b = z-x/a-cb−ax−y=c−by−z=a−cz−x

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Algebra and Applications Test 2

Question : 36 of 40

Marks: +1, -0

\frac{x}{b+c} = \frac{y}{c+a} = \frac{z}{a+b},

then

Solution: 👈: Video Solution

\frac{x}{b+c} = \frac{y}{c+a} = \frac{z}{a+b} = k

x = k(b + c)

y = k(c + a)

z = k(a + b)

From the above options

\frac{x-y}{b-a} = \frac{k(b+c)-k(c+a)}{b-a}

= \frac{bk+ck-ck-ak}{b-a}

= \frac{(b-a)k}{b-a} = k

...(i)

Similearly,

\frac{y-z}{c-b} = k

...(ii)

and

\frac{z-x}{a-c} = k

...(iii)

From (i), (ii) and (iii) we get

\frac{x-y}{b-a} = \frac{y-z}{c-b} = \frac{z-x}{a-c}

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