The equation _e x + _e (1 + x) = 0 can be written as:

Correct Answer is : x2+x−1=0x² + x - 1 = 0x2+x−1=0

Correct Answer is : x2+x−1=0x² + x - 1 = 0x2+x−1=0

Test Index

Logarithms Practice Test 2

Question : 18 of 39

Marks: +1, -0

The equation

\log_e x + \log_e (1 + x) = 0

can be written as:

Solution:

Concept:

Use the log product rule and convert the logarithmic equation into exponential form.

Explanation:

Combine the logs:

\log_e x+\log_e(1+x)=\log_e[x(1+x)]

Given

\log_e[x(1+x)]=0

x(1+x)=e^0=1

Expand:

x+x^2=1

Rearrange:

x^2+x-1=0

Answer:

x^2+x-1=0

, so the correct option is A.

Go to Question:

Prev Question

Next Question