Test Index

Powers and Roots Practice Test 3

© examsnet.com

Question : 2 of 40

Marks: +1, -0

If

\sqrt{1+\frac{735}{289}}=1+\frac{x}{17}

then find x.

16
15
17
18
725

Solution:

Concept:

Simplify the square root and then compare the equal fractions to find

x

.

Explanation:

Simplify inside the square root:

1+\frac{735}{289}=\frac{289+735}{289}=\frac{1024}{289}

Take the square root:

\sqrt{\frac{1024}{289}}=\frac{32}{17}

Given:

1+\frac{x}{17}=\frac{32}{17}

Write

1

as

\frac{17}{17}

:

\frac{17}{17}+\frac{x}{17}=\frac{32}{17}

So:

\frac{17+x}{17}=\frac{32}{17}

Therefore:

17+x=32

x=32-17=15

Answer:

x=15

© examsnet.com

Go to Question:

Prev Question

Next Question