Concept:Use the sum of cubes identity a3+b3=(a+b)(a2−ab+b2).Explanation:Let a=0.08 and b=0.02.Then 0.0016=0.08×0.02=ab.The given expression becomes a2−ab+b2a3+b3.Apply the identity: a3+b3=(a+b)(a2−ab+b2).Cancel the common factor a2−ab+b2.So the expression simplifies to a+b.Substitute back: a+b=0.08+0.02=0.10.Answer:0.1