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Simplification Test 6
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© examsnet.com
Question : 28 of 40
Marks:
+1
,
-0
1
10
\frac{1}{10}
10
1
​
of a pole is coloured red,
1
20
\frac{1}{20}
20
1
​
white,
1
30
\frac{1}{30}
30
1
​
blue,
1
40
\frac{1}{40}
40
1
​
black,
1
50
\frac{1}{50}
50
1
​
violet,
1
60
\frac{1}{60}
60
1
​
yellow and rest is green. If the length of the green portion of the pole is 12.08 meters. What is the length of the pole?
30 m
20 m
18 m
16 m
Validate
Solution:
The part of green portion
=
1
−
(
1
10
+
1
20
+
1
30
+
1
40
+
1
50
+
1
60
)
=1-\left(\frac{1}{10}+\frac{1}{20}+\frac{1}{30}+\frac{1}{40}+\frac{1}{50}+\frac{1}{60}\right)
=
1
−
(
10
1
​
+
20
1
​
+
30
1
​
+
40
1
​
+
50
1
​
+
60
1
​
)
=
1
−
60
+
30
+
20
+
15
+
12
+
10
600
=1-\frac{60+30+20+15+12+10}{600}
=
1
−
600
60
+
30
+
20
+
15
+
12
+
10
​
=
1
−
147
600
=
453
600
=1-\frac{147}{600}=\frac{453}{600}
=
1
−
600
147
​
=
600
453
​
Now,
453
600
x
=
12.08
\frac{453}{600}x = 12.08
600
453
​
x
=
12.08
∴
x
=
12.08
×
600
453
\therefore x = \frac{12.08\times 600}{453}
∴
x
=
453
12.08
×
600
​
=
1208
×
6
453
=\frac{1208\times 6}{453}
=
453
1208
×
6
​
= 16 m
Hence, length of the pole = 16 m
© examsnet.com
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