Test Index

Volumes Practice Test 3

© examsnet.com

Question : 40 of 40

Marks: +1, -0

In the above question, the cylinders formed will have their volumes in the ratio of

2 : 3
3 : 1
3 : 2
1 : 3

Solution:

In the first case :

2πr = 30

r =

\frac{15}{\pi}

cm and h = 20 cm

⇒ Volume

(V_1)

=

\pi r^{2}h

=

\frac{15 \times 15 \times 20}{\pi}

=

\frac{4500}{\pi}

cu cm

In the second case :

2πr = 20 ⇒ r =

\frac{10}{\pi}

cm and h = 30 cm

∴ Volume

(V_2)

=

\pi r^{2}h

=

\frac{10 \times 10 \times 30}{\pi}

=

\frac{3000}{\pi}

cu cm

Hence, ratio of the two volumes =

V_1 : V_2

=

\frac{4500}{\pi} : \frac{3000}{\pi}

= 3 : 2

© examsnet.com

Go to Question:

Prev Question