Concept:Express the reduced shares as multiples of a common variable k, then relate to the total sum.Explanation:Let the original shares of A, B, and C be a, b, c respectively.Given a+b+c=4850.After reducing by ₹15, ₹10, and ₹25, the remainders are in the ratio 3:4:5.So let a−15=3k, b−10=4k, c−25=5k.Then a=3k+15, b=4k+10, c=5k+25.Sum: (3k+15)+(4k+10)+(5k+25)=12k+50=4850.Solving: 12k=4800⇒k=400.Thus B's share b=4(400)+10=1600+10=1610.Answer:₹1610