Concept:Assume a common multiplier x to represent each salary from the given ratio, then form an equation using the given difference of products.Explanation:Let the salaries of the first, second, and third months be 2x, 4x, and 5x respectively.Product of the first two months: 2x×4x=8x2.Product of the last two months: 4x×5x=20x2.The difference between these products is given as 4,80,00,000.Since the product of the last two months is larger, subtract: 20x2−8x2=12x2.Set up equation: 12x2=4,80,00,000.Divide both sides by 12: x2=124,80,00,000​=40,00,000.Take the positive square root (salary cannot be negative): x=40,00,000​=2000.Second month salary: 4x=4×2000=8000.Thus the salary of the second month is Rs. 8,000.Answer:₹8,000