×60×60 = 3sec. When speed is constant then ratio of time taken is directly proportional to Distance covered So, Ratio of length of train to length of (train + tunnel) ⇒ 3:10 Let length of train = 3x Length of tunnel = 10x−3x = 7x ATQ, 7x−3x = 200 4x = 200 So, 3x = 150meter Speed of train =