Let total work be 90 units (LCM) So, efficiency of A + B = 5 units/days And efficiency of B + C = 3 units/day Let efficiency of C = a units/day So, efficiency of A = 2a units/day ATQ ⇒ 2a+B = 5 ..... (i) ⇒ B+a = 3 ..... (ii) From (i) and (ii) Efficiency of B = 1 unit/day ∴ required time =