RRB ALP CBT I 17 Feb 2026 Shift 1 Paper

Concept:The total surface area of the combined toy is the sum of the cone’s curved surface area, the frustum’s curved surface area, and the frustum’s larger base area.The common circular base between the cone and the frustum is internal, so it is not included.Explanation:For the cone, radius $r = 5$ cm and height $h = 12$ cm.Slant height of cone: $l = \sqrt{h^2 + r^2} = \sqrt{12^2 + 5^2} = \sqrt{169} = 13$ cm.Curved surface area of cone: $\pi r l = \pi \times 5 \times 13 = 65\pi$ cm$^2$.For the frustum, smaller radius $r = 5$ cm, larger radius $R = 22$ cm, and slant height $L = 32$ cm.Curved surface area of frustum: $\pi (R + r) L = \pi (22 + 5) \times 32 = 864\pi$ cm$^2$.Area of the larger base: $\pi R^2 = \pi \times 22^2 = 484\pi$ cm$^2$.Total surface area of the toy:$65\pi + 864\pi + 484\pi = 1413\pi$ cm$^2$.Answer:$1413\pi$ cm$^2$ Therefore, the correct option is B.