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RRB ALP CBT I 26 Nov 2024 Shift 2 Paper

Question : 58 of 75

Marks: +1, -0

(6, 54, 3)

Solution:

Concept:

The middle number is obtained by multiplying the first number by the square of the third number.

Explanation:

For the given set

(11, 44, 2)

11 \times 2^2 = 11 \times 4 = 44

For the given set

(6, 54, 3)

6 \times 3^2 = 6 \times 9 = 54

Now check the options using the same logic.

Option A:

(12, 72, 3)

gives

12 \times 3^2 = 12 \times 9 = 108 \neq 72

Option B:

(2, 32, 4)

gives

2 \times 4^2 = 2 \times 16 = 32

Option C:

(7, 98, 2)

gives

7 \times 2^2 = 7 \times 4 = 28 \neq 98

Option D:

(10, 50, 5)

gives

10 \times 5^2 = 10 \times 25 = 250 \neq 50

Only option B follows the same relation.

Answer:

(2, 32, 4)

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