Concept:This is a circular seating arrangement problem where all persons face the centre, so left and right are determined from their perspective inside the circle.
Explanation:We start by placing the given clues one by one.
R sits to the immediate left of U. So the order is U - R (clockwise or anticlockwise? Since facing centre, immediate left means the person to his left in the circle. We can assume a clockwise sequence for convenience.)
Place U and then R to its left. Let’s write clockwise order: ... U, R ...
A sits third to the left of U. Counting three positions to the left of U gives the arrangement: ... ? , ? , A , U ... Actually third left means two persons between them, so A is two steps clockwise from U? Better: From U, moving left (clockwise) three places gives the third person. So sequence: U, (first left), (second left), A. So between U and A there are two persons. We already have R as immediate left, so the sequence becomes: U, R, ?, A. That ? is the second left of U, unknown yet.
C sits second to the left of T. So from T, moving left two places gives C. Means one person between them: T, ?, C.
B sits to the immediate left of C. So C is immediately left of B? Actually "B sits to the immediate left of C" means from C's perspective, B is on his immediate left. So order: ... B, C ... (B then C clockwise).
Now combine all clues. We have a circular arrangement of 7 persons: A, B, C, R, S, T, U. We must place them all.
From the clues we have: U, R, ?, A ; and also T, ?, C ; and B, C together.
Try to fit: The sequence U, R, ?, A gives us positions for U, R, and A. The unknown between R and A must be one person. That person could be T or C or B or S.
Also, consider clue: C sits second to the left of T. If we try to place T such that C is two left, we can test.
Let’s number positions 1 to 7 in clockwise order. Let position 1 be U. Then immediate left (clockwise) is position 2 = R. Third left of U means from U count three clockwise: pos1(U), pos2(R), pos3(?), pos4(A). So pos3 is unknown, pos4 = A.
Now we have pos1=U, pos2=R, pos4=A. Remaining positions: 3,5,6,7 for B,C,T,S.
Clue: B sits immediate left of C. So in clockwise order B then C consecutively.
Clue: C sits second left of T. So from T, two steps clockwise gives C; meaning one person between T and C in clockwise direction. So T, ?, C in that order (clockwise).
Try to place T and C. Possibility: If we put T at pos5, then second left (clockwise) is pos7 (since pos5 → pos6 → pos7). So pos7 would be C. Then immediate left of C (pos7) would be B at pos6 (since B before C clockwise). That fits: pos5=T, pos6=B, pos7=C. Then remaining pos3 is S.
Check all: positions: 1=U,2=R,3=S,4=A,5=T,6=B,7=C. Verify: R immediate left of U? pos2=left of pos1, yes. B immediate left of C? pos6 left of pos7, yes. C second left of T? from T(pos5) moving two left: pos6, pos7 → C is at pos7, yes. A third left of U? from U(pos1) moving three left: pos2, pos3, pos4 → A at pos4, yes. All persons are present. So arrangement is valid.
Now question: Who sits third to the right of S? S is at position 3. Third to the right means moving three positions anticlockwise (since facing centre, right is anticlockwise). From pos3, move anticlockwise (decreasing position numbers, wrapping): pos2, pos1, pos7. So third right is at pos7 which is C.
Answer:C
