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RRB Group D 15-Oct-2018 Shift 1 Solved Paper
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© examsnet.com
Question : 5
Total: 84
A smallest 5 -digit number, when divided by 4 , 5 and
7
,
leaves a remainder of 3 in each case. The number is:
10013
10003
10077
10083
Validate
Solution:
L
C
M
of 4,5 and 7
=
2
×
2
×
5
×
7
=
140
Smallest five digit no
=
10
,
000
=
140
×
72
+
3
=
10080
+
3
=
10083
© examsnet.com
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