Concept:This is a circular seating arrangement problem.
All persons face the centre, so "right" means clockwise direction.
We arrange positions step-by-step using the given clues.
Explanation:There are 7 seats: A, B, C, D, E, F, G.
Step 1: "C sits third to the right of D."
Place D at any seat. Count 3 steps clockwise from D to get C.
So D and C have two persons between them (like D _ _ C).
Step 2: "E sits second to the right of C."
From C, move 2 steps clockwise to get E.
So C and E have one person between them (C _ E).
Step 3: "F is the immediate neighbour of B and C."
F is adjacent to both B and C.
Since C already has neighbours, place F next to C.
Then B must be adjacent to F, so B goes on the other side of F.
Step 4: "G is not an immediate neighbour of D."
Now place remaining persons A and G in the empty seats.
G cannot be next to D, so G must occupy a seat away from D.
After placing all, the order around the circle becomes: D, B, F, C, E, A, G (clockwise).
Check: D → 3 right = C; C → 2 right = E; F neighbours B and C; G not next to D.
Now count people between A and G when counted from the left of G.
"Left of G" means anticlockwise direction (since facing centre).
From G, moving anticlockwise: after G comes D, then B, then F, then C, then E, then A.
The persons between G and A (excluding A and G) are D, B, F, C, E — that is 5 persons? Wait careful.
Actually, "from the left of G" means we start at G and go anticlockwise, counting the people we encounter until A. But the question asks: "How many people sit between A and G when counted from the left of G?"
Between A and G means the persons that are strictly between them on that path.
From G anticlockwise to A: G → D → B → F → C → E → A. So between G and A we have D, B, F, C, E — that's 5 people? That can't be right because total seats are 7. Let's check our arrangement again.
We must ensure all seats are filled correctly. Let's assign positions 1 to 7 clockwise. Let D be at position 1. C is third to right (clockwise) so at position 4. E second to right of C: position 6. F is immediate neighbour of B and C. C is at 4, so F could be at 3 or 5. If F at 5, then B must be at 6 (adjacent to F) but 6 is occupied by E. So F cannot be at 5. Thus F must be at 3. Then B must be adjacent to F, so B at 2 or 4. But 4 is C, so B at 2. Now we have: D=1, B=2, F=3, C=4, E=6. Empty positions: 5 and 7. G must not be adjacent to D (D is at 1). Adjacent positions to 1 are 7 and 2. 2 is B, so G cannot be at 7. Hence G must be at 5. Then A goes at 7. So final clockwise order: 1-D, 2-B, 3-F, 4-C, 5-G, 6-E, 7-A.
Now count between A (position 7) and G (position 5) from left of G. Left means anticlockwise. From G at 5 anticlockwise: 5→4→3→2→1→7. So between G and A along this path: positions 4 (C), 3 (F), 2 (B), 1 (D) — that's 4 people. And position 7 is A itself, not counted. So answer is 4.
Answer:Four people sit between A and G when counted from the left of G.
Hence, the correct option is "B. Four".
