Concept:In a circular arrangement where everyone faces the centre, the left side is clockwise and the right side is anticlockwise.
Explanation:Place D at position 0 (reference).
I sits immediately left of D → I is at position 1 (clockwise from D).
K sits third to the left of D → K is at position 3 (clockwise from D).
So the clockwise order so far: D, I, (position 2), K.
J is an immediate neighbour of both B and K. J must be adjacent to K.
If J were at position 2, its neighbours would be I and K, not B. So J cannot be at position 2.
Thus J is at position 4. Then J’s other neighbour (position 5) must be B.
So far placed: D(0), I(1), (2), K(3), J(4), B(5). Remaining persons: C and L. Position 2 and position 6 are empty.
L is not an immediate neighbour of K. K’s neighbours are position 2 and position 4. Position 4 is J, so L cannot be at position 2. Hence L goes to position 6, and C goes to position 2.
Final clockwise order: D, I, C, K, J, B, L.
From C, move right (anticlockwise): first right is I, second right is D.
Thus D sits second to the right of C.
Answer:D
