GIVEN: x – y = 12 and x2+y2 = 156 CONCEPT: Here we need to carefully look at the question and check whether (x+y)2or(x–y)2 will be applied FORMULAE USED: (x–y)2 = x2+y2 – 2xy CALCULATION: Considering the given statement x – y = 12 and x2+y2 = 156 (x–y)2=x2+y2 – 2xy Putting the values we get, (12)2=x2+y2–2xy ⇒ 144 = 156 – 2xy ⇒ 2xy = 12 ⇒ xy = 6 ∴ Required value is 6