RRB Group D Model Paper 3 with solutions

(2) Let (A + C) complete the work in ‘a’ days. So B will complete the work in 3a days.

1

a

+

1

3a

=

1

40

→ 3a = 40 ⇒ a =

40

3

Let (A + B) complete the work in n days. So C will complete the work in 2n days.

1

n

+

1

2n

=

1

10

⇒ n =

30

2

= 15
(A + B + C)'s1 day's work =

1

10

1

A

+

1

40

+

1

30

=

1

10

⇒

1

A

=

12−3−4

120

=

5

120

=

1

24

Therefore, A will complete the work in 24 days.