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RRB Junior Engineer Stage 1 Model Papers 6
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© examsnet.com
Question : 3
Total: 99
Two parallel chords of a circle, of diameter 20 cm lying on the opposite sides of the centre are of lengths 12 cm and 16 cm. The distance between the chords is
16cm
24cm
14 cm
20 cm
Validate
Solution:
O
A
=
O
C
=
10
c
m
A
B
=
12
c
m
A
P
=
P
B
=
6
c
m
C
D
=
16
c
m
C
Q
=
Q
D
=
8
c
m
From ∆OCQ,
O
Q
=
√
10
2
−
8
2
=
√
18
×
2
=
6
c
m
From ∆OAP
O
P
=
√
(
10
2
−
6
2
)
=
√
16
×
4
=
8
c
m
∴
P
Q
=
6
+
8
=
14
c
m
© examsnet.com
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