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RRB Junior Engineer Stage 1 Model Papers 9
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© examsnet.com
Question : 6
Total: 100
The perimeters of two similar triangle ∆ABC and ∆PQR are 36 cm and 24 cm respectively. If PQ = 10 cm, then AB is:
25 cm
10 cm
15 cm
20 cm
Validate
Solution:
A
B
P
Q
=
B
C
Q
R
=
C
A
R
P
=
A
B
+
B
C
+
C
A
P
Q
+
Q
R
+
R
P
⇒
A
B
P
Q
=
36
24
⇒
A
B
10
=
36
24
⇒
A
B
=
36
×
10
24
=
15
c
m
© examsnet.com
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