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RRB NTPC 2014 Paper

Question : 43 of 100

Marks: +1, -0

Solution:

(2) Suppose he sells x lemons at 25% profit and (100 – x) at 10%profit.

Let cost price of one lemon be ₹1.Selling price of x lemons =

x+\frac{x}{4}=\frac{5x}{4}

Selling price of (100 – x) lemons =

(100-x)+\frac{1}{10}(100-x)

=1.1(100-x)=110-1.1x

Net profit =

\frac{110-1.1x+\frac{5x}{4}-100}{100} \times 100 = 16

\Rightarrow 10+0.15x=16

\Rightarrow x=\frac{6}{0.15}=40

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