The value of3 ÷ ≤ft[ (8-5) ÷ ≤ft\{ (4-2) + ≤ft[ 2 + 8/13 ] \} ]is

Correct Answer is : 131713/171713

Correct Answer is : 131713/171713

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RRB NTPC Mains or Stage 2 Model Paper 7 with solutions

Question : 2 of 120

Marks: +1, -0

The value of

3 \div \left[ (8-5) \div \left\{ (4-2) + \left[ 2 + \frac{8}{13} \right] \right\} \right]

Solution:

Concept:

Use BODMAS/PEMDAS to simplify nested brackets from innermost to outermost.

Explanation:

Step 1: Simplify the innermost bracket:

2 + \frac{8}{13} = \frac{26+8}{13} = \frac{34}{13}

Step 2: Simplify the curly bracket:

(4-2) \div \left[2 + \frac{8}{13}\right] = 2 \div \frac{34}{13} = 2 \times \frac{13}{34} = \frac{13}{17}

Step 3: Simplify the square bracket:

(8-5) \div \frac{13}{17} = 3 \times \frac{17}{13} = \frac{51}{13}

Step 4: Final division:

3 \div \frac{51}{13} = 3 \times \frac{13}{51} = \frac{13}{17}

Answer:

\frac{13}{17}

, which is option B.

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