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RRB NTPC Mains or Stage 2 Model Paper 8 with solutions
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© examsnet.com
Question : 24
Total: 120
From the top of a cliff 200 m high, the angles of depression of the top and bottom of a tower are observed to be 30º and 45º, respectively. What is the height of the tower?
400 m
400
√
3
m
400
√
3
m
None of these
Validate
Solution:
In ΔACB, tan 30º
=
200
−
h
x
=
1
√
3
=
500
−
h
x
⇒
x
=
(
200
−
h
)
√
3
... (i)
In ΔADE,
tan
45
º
=
200
x
⇒
1
=
200
x
⇒
x
=
200
m
From Eq. (i)
200
=
(
200
–
h
)
√
3
⇒
h
=
200
[
√
3
−
1
√
3
]
m
© examsnet.com
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