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RRB NTPC Mains or Stage 2 Model Paper 9 with solutions

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Question : 13 of 120

Marks: +1, -0

In the figure , if

\frac{NT}{AB} = \frac{9}{5}

and if MB = 10, find MN.

5
4
28
18

Solution:

Concept:

Similar triangles have corresponding sides in the same ratio.

Explanation:

In the figure,

\triangle MBA \sim \triangle MNT

by the AA similarity criterion.

So, their corresponding sides are proportional:

\frac{MB}{MN}=\frac{AB}{NT}

Given

\frac{NT}{AB}=\frac{9}{5}

, so

\frac{AB}{NT}=\frac{5}{9}

.

Substitute

MB=10

:

\frac{10}{MN}=\frac{5}{9}

5 \times MN = 10 \times 9

MN=\frac{90}{5}=18

Answer:

MN=18

Correct option: D

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