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RRB RPF RPSF SI and CONS Model Papers 3 with solutions
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© examsnet.com
Question : 11
Total: 120
A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m, then the altitude of the triangle is :
100 m
200 m
100
√
2
m
10
√
2
m
Validate
Solution:
(b) Let the common base be
x
m.
Now, area of the triangle = area of the parallelogram
1
2
×
x
×
Altitude of the triangle
=
x
×
100
Altitude of the triangle = 200 m
© examsnet.com
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