(a) Working with the options, for x = 0, the least value of f(x)=3x+3−x=2Alternate : Let A=3x and A1​=3−x ⇒ Both are positive. Now, A.M. of A and A1​ is greater than or equal to their G.M.i.e. 2A+A1​​≥A⋅A1​​or A+A1​≥2or 3x+3−x≥2