Let ba​=dc​=fe​=p then a = pb, c = pd and e = pf. Now, In option (1),b−3d−f3a−3c−5e​=p(b−3d−f3b−3d−5f​)In option (2),b−d−fa−3c−5e​=p(b−d−fb−3d−5f​)In option (3),b−d−5fa−c−e​=p(b−d−5fb−d−f​)In option (4),b+3d−5fa+3c−5e​=p(b+3d−5fb+3d−5f​)=pThus, ba​=dc​=fe​⇒p=b+3d−5fa+3c−5e​