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RRB Technician Grade 1 Model Paper 3

Question : 55 of 100

Marks: +1, -0

The value of

18\div [92\div 2 of 8+3\frac{1}{4}]

is:

Solution:

Concept:

Apply the VBODMAS rule: Bracket, Of, Division, Multiplication, Addition, Subtraction.

Explanation:

Given expression:

18\div \left[92\div 2\text{ of }8+3\frac{1}{4}\right]

First, solve "of":

2\text{ of }8 = 2\times 8 = 16

Convert mixed fraction:

3\frac{1}{4} = \frac{13}{4}

Now simplify inside the bracket:

92\div 16 + \frac{13}{4} = \frac{92}{16} + \frac{13}{4}

\frac{92}{16} = \frac{23}{4}

, so the bracket becomes:

\frac{23}{4} + \frac{13}{4} = \frac{36}{4} = 9

Therefore:

18\div 9 = 2

Answer:

2

Option A. 2

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