RRB Technician Grade I 19 Dec 2024 Shift 2 Paper

Concept:Each letter-cluster pair follows a fixed positional shift pattern between the first and second clusters.Explanation:Compare the alphabetical positions of the corresponding letters in each pair.For $\mathrm{SL} \rightarrow \mathrm{RX}$: $\mathrm{S}(19) \rightarrow \mathrm{R}(18)$ is $-1$, and $\mathrm{L}(12) \rightarrow \mathrm{X}(24)$ is $+12$.So the pattern is: first letter $-1$, second letter $+12$.For $\mathrm{RK} \rightarrow \mathrm{QW}$: $\mathrm{R}(18) \rightarrow \mathrm{Q}(17)$ is $-1$, and $\mathrm{K}(11) \rightarrow \mathrm{W}(23)$ is $+12$.This also follows the same pattern.For $\mathrm{LE} \rightarrow \mathrm{KQ}$: $\mathrm{L}(12) \rightarrow \mathrm{K}(11)$ is $-1$, and $\mathrm{E}(5) \rightarrow \mathrm{Q}(17)$ is $+12$.This follows the same pattern.For $\mathrm{OH} \rightarrow \mathrm{MT}$: $\mathrm{O}(15) \rightarrow \mathrm{M}(13)$ is $-2$, and $\mathrm{H}(8) \rightarrow \mathrm{T}(20)$ is $+12$.Here, the first-letter shift is $-2$, not $-1$.Therefore, this pair does not follow the common pattern.Answer:$\mathrm{OH} \text{ - } \mathrm{MT}$ (Option 1) is the odd one out.