SAT Mathematics Practice Test 4

Adding 4 to each side of the inequality $3p-2 \ge 1$ yields the inequality $3p+2 \ge 5$. Therefore, the least possible value of $3p+2$ is 5.Choice B is incorrect because it gives the least possible value of $3p$, not of $3p+2.$ Choice C is incorrect. If the least possible value of $3p+2$ were 2, then it would follow that $3p+2 \ge 2$. Subtracting 4 from each side of this in equality would yield $3p-2 \ge -2$. This contradicts the given inequality, $3p-2 \ge 1$.Therefore, the least possible value of $3p+2$ cannot be 2. Choice D is incorrect because it gives the least possible value of p, not of $3p+2$.