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SBI PO 4 Jan 2021 Paper

Direction (60 - 65) -: Study the given information carefully and answer the questions that follow.

The table given below shows the capacity of 5 buses(A, B, C, D, E) and the percentage of seats that were filled out of the total seating capacity of the buses.

Bus	Total seating capacity	Percentage of seats filled
A	$20$	$60\%$
B	$30$	$80\%$
C	$15$	$60\%$
D	N/A	$70\%$
E	N/A	$66.66\%$

Some of the data is missing and is denoted as N/A

Note:

A) The total number of vacant seats in all the 5 buses together were 40

B) The number of seats in buses D and E together were 65

Question : 61 of 100

Marks: +1, -0

If the number of vacant seats was distributed in a degree pie-chart, what would have been the central angle for bus A?

75.6°
104.4°
72°
54°
86.4°

Validate

Solution:

For bus A,

Number of filled seats = 20 × 0.6 = 12

Number of vacant seats = 20 − 12 = 8

Similarly, for bus B and C

Number of filled seats for bus B = 30 × 0.8 = 24

Number of vacant seats for bus B = 30 − 24 = 6

Number of filled seats for bus C = 15 × 0.6 = 9

Number of vacant seats for bus C = 15 − 9 = 6

Let the number of seats in buses D and E be D and E respectively and number of vacant seats in buses D and E be D’ and E’ respectively.

D + E = 65….(1)

D’ + E’ = 40 – (8 + 6 + 6) = 20

⇒ D × (1 – 0.7) + E × (1 – 0.66) = 20

⇒ 0.3D + 0.33E = 20….(2)

Using equations (1) and (2)

D = 50, E = 15, D’ = 15, E’ = 5

Bus	Number of seats	Number of filled seats	Number of vacant seats
A	$20$	12	8
B	$30$	24	6
C	$15$	9	6
D	50	35	15
E	15	10	5

Required central angle

=\frac{8}{8+6+6+15+5} \times 360 = 72^{\circ}

Hence, the required answer is option C.

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