Test Index

Sequence and Series

Question : 55 of 86

Marks: +1, -0

7,13,19, . . . . .97

Solution:

Concept:

The number of terms in an arithmetic progression is found using the formula for the nth term.

Explanation:

Here, first term

a = 7

, common difference

d = 13 - 7 = 6

Let the last term be

a_n = 97

Using

a_n = a + (n-1)d

, we have:

7 + (n-1) \cdot 6 = 97

(n-1) \cdot 6 = 90

n-1 = 15

n = 16

Answer:

The number of terms is 16.

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