Concept:Let the four numbers in A.P. be a, a+d, a+2d, a+3d.Explanation:Given: sum of second and third is 22.(a+d)+(a+2d)=22⟹2a+3d=22.Given: product of first and fourth is 85.a(a+3d)=85.From first equation, a=222−3d​.Substitute into second:222−3d​(222−3d​+3d)=85222−3d​⋅222+3d​=854484−9d2​=85⟹484−9d2=340⟹9d2=144⟹d=±4.For d=4, a=222−12​=5. Numbers: 5,9,13,17.For d=−4, a=17, same set reversed.Answer:The four numbers are 5,9,13,17, which matches option C.