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SRMJEE 2019 Paper with key
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© examsnet.com
Question : 73
Total: 140
The inverse of the function
f
(
x
)
=
2
x
−
2
−
x
e
x
+
e
−
x
+
2
is given by
log
e
(
x
−
2
x
+
2
)
1
2
log
e
(
x
−
1
x
+
1
)
1
2
log
e
(
1
−
x
x
−
3
)
1
2
log
e
(
x
−
1
x
+
1
)
1
3
Validate
Solution:
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