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SRMJEE 2019 Paper with key
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© examsnet.com
Question : 97
Total: 140
If the circles
x
2
+
y
2
+
2
x
+
2
k
y
+
6
=
0
,
x
2
+
y
2
+
2
k
y
+
k
=
0
intersect orthogonally, then kis
2
(
o
r
)
−
3
2
−
2
(
o
r
)
−
3
2
2
(
o
r
)
3
2
−
2
(
o
r
)
3
2
Validate
Solution:
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