SSC CGL 26 Oct 2014 Shift 2 Paper

Radius of circle = x cm.
Side of square = y cm.
Side of equilateral triangle = z cm.
Circumference of circle = Perimeter of square = Perimeter of equilateral triangle
⇒ 2 p x = 4 y = 3 z
⇒ x =

4y

2π

=

2y

π

z =

4y

3

Area of circle ‘C’ = π x2
= π ×

4

π2

y2 =

4

π

y2 > y2
Area of square ‘S’ = y2
Area of triangle ‘T’ =

√3

4

z2
=

√3

4

×

4×4

3×3

y2
=

4

3√3

y2 < y2
∴ T < S < C