SSC CGL 31 Aug 2016 Paper

Suppose present age of man = 4x years Present age of his wife = 3x years After 4 years $\frac{4x+4}{3x+4}$ = $\frac{9}{7}$ ⇒ 28x + 28 = 27Xx + 36 ⇒ 28x - 27x = 36 - 28 ∴ x = 8 Present age of man = 4x = 4 × 8 = 32 years Present age of his wife = 3x = 3 × 8 = 24 years Suppose, they were married y years ago According to question $\frac{32-y}{24-y}$ = $\frac{5}{3}$ ⇒ 96 - 3y = 120 - 5y ⇒ 5y - 3y = 12 - 96 ⇒ 2y = 24 ∴ y = 12