Concept:Replace each letter with its given arithmetic operator, then evaluate using BODMAS.Explanation:Given: P=×, Q=−, S=+, R=÷.Check option A: 7S56P2R28=11 becomes 7+56×2÷28=11.First solve 56×2=112.Then 112÷28=4.Finally 7+4=11, so option A is true.Check other options:B: 36÷6×2+4=16=19.C: 64÷8×3+6=30=72.D: 36÷9+4×2=12=14.Thus only option A satisfies the condition.Answer:Option A: 7S56P2R28=11 is correct.