Test Index

SSC CGL Model Paper 14

Question : 5 of 100

Marks: +1, -0

In the following question, select the odd letters from the given alternatives.

Solution:

Concept:

In letter odd-one-out questions, convert letters to their alphabet positions and check the numerical pattern.

Explanation:

Use positions:

A=1

B=2

\dots

Z=26

For

\mathrm{BOH}

B=2

O=15

H=8

;

B+13=O

and

B+6=H

For

\mathrm{ERK}

E=5

R=18

K=11

;

E+13=R

and

E+6=K

For

\mathrm{HUO}

H=8

U=21

O=15

;

H+13=U

, but

H+6=14=\mathrm{N}

, not

O

For

\mathrm{KXQ}

K=11

X=24

Q=17

;

K+13=X

and

K+6=Q

\mathrm{HUO}

does not follow the common pattern.

Answer:

Option C:

\mathrm{HUO}

is the odd one.

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