Test Index

SSC CGL Model Paper 5

Question : 5 of 100

Marks: +1, -0

If PRIMATE is coded as MOFJXQB, COW be coded as?

Solution:

Concept:

Each letter is shifted backward by a fixed number of positions in the alphabet.

Explanation:

Compare

\mathrm{PRIMATE}

and

\mathrm{MOFJXQB}

letter by letter.

\mathrm{P} \rightarrow \mathrm{M}

means shift back by

3

\mathrm{R} \rightarrow \mathrm{O}

also shows a shift back by

3

\mathrm{I} \rightarrow \mathrm{F}

\mathrm{M} \rightarrow \mathrm{J}

\mathrm{A} \rightarrow \mathrm{X}

confirm the same rule using wrap-around.

So, apply the same

-3

shift to

\mathrm{COW}

\mathrm{C} - 3 = \mathrm{Z}

\mathrm{O} - 3 = \mathrm{L}

\mathrm{W} - 3 = \mathrm{T}

Thus,

\mathrm{COW}

is coded as

\mathrm{ZLT}

Answer:

\mathrm{ZLT}

, which is option A.

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