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SSC CGL Model Paper 6

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Question : 13 of 100

Marks: +1, -0

If PRIMATE is coded as MOFJXQB, then how will COW be coded as ?

ZLT
EDC
RFV
TGB

Solution:

Concept:

In fixed-shift letter coding, each letter is moved by the same number of positions in the alphabet.

Explanation:

Compare

\mathrm{PRIMATE}

with

\mathrm{MOFJXQB}

:

\mathrm{P}\rightarrow \mathrm{M}

,

\mathrm{R}\rightarrow \mathrm{O}

,

\mathrm{I}\rightarrow \mathrm{F}

,

\mathrm{M}\rightarrow \mathrm{J}

,

\mathrm{A}\rightarrow \mathrm{X}

,

\mathrm{T}\rightarrow \mathrm{Q}

,

\mathrm{E}\rightarrow \mathrm{B}

.

Each letter is shifted

3

places backward, i.e.

-3

.

Here

\mathrm{A}-3

wraps to

\mathrm{X}

.

Now apply the same rule to

\mathrm{COW}

:

\mathrm{C}-3=\mathrm{Z}

\mathrm{O}-3=\mathrm{L}

\mathrm{W}-3=\mathrm{T}

So the code is

\mathrm{ZLT}

.

Answer:

\mathrm{ZLT}

(Option A)

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