SSC CGL Tier I 12 Sep 2025 Shift 2 Paper

Concept:When interest is compounded annually for a fractional year, first find the amount for the full years using compound interest, then add simple interest for the remaining months.Explanation:Given: Principal $P = ₹8,000$, Rate $R = 12\%$ per annum, Time $= 3$ years $4$ months $= 3\frac{1}{3}$ years.First, calculate amount for the first 3 years using compound interest formula: $A = P \times (1 + \frac{R}{100})^n$.$A_3 = 8000 \times (1 + \frac{12}{100})^3 = 8000 \times (1.12)^3$.$(1.12)^3 = 1.404928$, so $A_3 = 8000 \times 1.404928 = ₹11,239.42$.Now, for the remaining 4 months ($\frac{1}{3}$ year), apply simple interest on the amount after 3 years.Simple Interest for 4 months: $SI = \frac{P \times R \times T}{100} = \frac{11239.42 \times 12 \times \frac{1}{3}}{100} = 11239.42 \times 0.04 = ₹449.58$.Final amount after $3\frac{1}{3}$ years: $A = 11239.42 + 449.58 = ₹11,689$.Compound Interest = Final Amount − Principal = $11689 - 8000 = ₹3,689$.Answer:₹3,689 (Option C)