SSC CGL Tier I 14 Sep 2025 Shift 1 Paper

Concept:The average height of a section is the total of all heights divided by the number of students in that section.Explanation:First calculate the total height for Section A.Multiply each height by its frequency and add:$1.50 \times 5 = 7.50$$1.65 \times 9 = 14.85$$1.52 \times 11 = 16.72$$1.55 \times 14 = 21.70$$1.78 \times 6 = 10.68$$1.77 \times 7 = 12.39$$1.70 \times 4 = 6.80$Total height = $7.50 + 14.85 + 16.72 + 21.70 + 10.68 + 12.39 + 6.80 = 90.64$ metres.Total students in Section A = $5 + 9 + 11 + 14 + 6 + 7 + 4 = 56$.Average height of Section A = $90.64 \div 56 \approx 1.6186$ metres.Now compute for Section B.Total height:$1.50 \times 4 = 6.00$$1.65 \times 8 = 13.20$$1.52 \times 13 = 19.76$$1.55 \times 10 = 15.50$$1.78 \times 7 = 12.46$$1.77 \times 5 = 8.85$$1.70 \times 3 = 5.10$Sum = $6.00 + 13.20 + 19.76 + 15.50 + 12.46 + 8.85 + 5.10 = 80.87$ metres.Total students in Section B = $4 + 8 + 13 + 10 + 7 + 5 + 3 = 50$.Average height of Section B = $80.87 \div 50 = 1.6174$ metres.Since $1.6186 > 1.6174$, Section A has the higher average height.Answer:A