Let line l perpendicularly bisects line joining A(5,-3) and B(0,2) at C, thus C is the mid point of AB. Now, slope of AB =
y2−y1
x2−x1
=
(2+3)
(0−5)
=
5
−5
=−1 Let slope of line l=m Product of slopes of two perpendicular lines = -1 ⇒ m×−1=−1 ⇒ m=1 Equation of a line passing through point (x1,y1) and having slop m is (y−y1)=m(x−x1) ∴ Equation of line l ⇒ (y+