Let ∠ A = 60° and BD be the shorter diagonal = 8 cm The diagonals of a rhombus bisect each other at right angle and also bisect the angles of rhombus. ⇒ ∠OAD = 30° and OD = 4 cm In △OADtan(∠OAD)=
OD
OA
⇒ tan(30)=
4
OA
⇒
1
√3
=
4
OA
⇒ OA=4√3 Thus, AC =2×4√3=8√3 = cm ∴ Area of rhombus =