Radius =5cm We know that, the length of two chords are equal, then the perpendicular distance of the chords from the centre are equal. ∴ OA=OB Given, AB=6cm ∴ OA+OB=6 ⇒ OA=OB=3cm lnΔOBC OB2+BC2=OC2 ⇒ BC2=52−32=25−9=16 ∴BC=√16=4cm and length of each chord =2×4=8cm.