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SSC CHSL 6 Mar 2018 Shift 1 Paper

Section: English Language

Question : 10 of 106

Marks: +1, -0

What is the average of first 11 multiples of 11?

Solution:

First eleven multiples of 11 will form an arithmetic progression : 11,22,33,.......,121

First term, and common difference,

d = 11

Sum

n

of terms =

\frac{n}{2} (a + l)

⇒

S_{11} = \frac{11}{2} (11 + 121)

11 \times 66

Now, average of 11 terms =

= \frac{11 \times 66}{11} = 66

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